Question 478021
Find three consecutive positive integers such that the sum of the squares of the first and second equals the square of the third.
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1st: x-1
2nd: x 
3rd: x+1
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Equation:
(x-1)^2 + x^2 = (x+1)^2
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x^2-2x+1 + x^2 = x^2+2x+1
x^2 -4x = 0
x(x-4) = 0
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Positive solution:
Let x = 4
1st: x-1 = 3
2nd: x = 4
3rd: x+1 = 5
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Cheers,
Stan H.
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