Question 477791
{{{(y-1)/2  +   (y+1)/3  =  (2y+5)/3}}}

LCD = 6
multiply the equation by the LCD 6 

{{{(y-1)*3  +   (y+1)*2  =  (2y+5)*2}}}

3y-3+2y+2=4y+10

3y+2y-4y=10-2+3
y=11

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