Question 477567
Please help me solve this log equation -3/4log16y4+2/3log8y3
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It's not an equation, there's no equal sign ???
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If you mean
{{{ (-3/4)log(16y^4) + (2/3)log(8y^3)}}}
= {{{-3log(2y) + 2log(2y)}}}
= - log(2y)
or log(1/2y)