Question 477424
NO, it's not correct.


{{{(x + 3)(x - 3) = -8}}}...first multiply left side


{{{x^2-3x+3x - 9 = -8}}}


{{{x^2-cross(3x)+cross(3x) - 9 = -8}}}


{{{x^2-9 = -8}}}......add {{{8}}} to both sides


{{{x^2-9+8 = -8+8}}}


{{{x^2-1 =0}}}....factor


{{{(x-1)(x+1) =0}}}.........NOW, when you have a product equal to {{{zero}}}, you can find solutions:


{{{x-1 =0}}}.......->......{{{x=1}}}


{{{x+1 =0}}}.......->......{{{x=-1}}}



let's see it on a graph:


{{{ graph( 500, 500, -10,10, -10, 10, (x + 3)(x - 3) +8) }}}