Question 477382
{{{(12x^5)/(18x^3) = (2*2*3*x*x*x*x*x)/(2*3*3x*x*x) =

(cross(2)*2*3*x*x*x*x*x)/(cross(2)*3*3x*x*x) =

(2*3*x*x*x*x*x)/(3*3x*x*x) = (2*cross(3)*x*x*x*x*x)/(cross(3)*3x*x*x) =

(2*x*x*x*x*x)/(3x*x*x) = (2*cross(x)*x*x*x*x)/(3cross(x)*x*x) =

(2*x*x*x*x)/(3x*x) = (2*cross(x)*x*x*x)/(3cross(x)*x) =

(2*x*x*x)/(3x) =  (2*cross(x)*x*x)/(3cross(x)) =

(2*x*x)/3 =  (2x^2)/3}}}

Easier way:

6 goes into both 12 and 18.  6 goes into 12 2 times, so you'll
have a 2 on the top.  6 goes into 18 3 times so you'll have a
3 on the bottom.  Subtract the exponents 5-3=2 and so you'll have
x² on the top since the larger exponent was on the top, and so you
just write down the answer as {{{(2x^2)/3}}}.

Edwin</pre>