<PRE><B>Question 477122</B>
Suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50 inches.
:
2L + 2W = 50
Simplify, divide by 2
L + W = 25
:
&quot;the width of a rectangle is 5 inches shorter than the length&quot;
W = L - 5
:
Replace W with (L-5) in the simplified equation
L + (L-5) = 25
2L = 25 + 5
2L = 30
L = 15 inches is the Length
then. obviously
15 - 5 = 10 in is the width
:
:
Check by finding the perimeter
2(15) + 2(10) = 50
 </PRE>