Question 477247


{{{3x^2=39}}} Start with the given equation.



{{{x^2=(39)/(3)}}} Divide both sides by {{{3}}}.



{{{x^2=13}}} Reduce.



{{{x=""+-sqrt(13)}}} Take the square root of both sides.



{{{x=sqrt(13)}}} or {{{x=-sqrt(13)}}} Break up the "plus/minus" to form two equations.


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Answer:



So the solutions are {{{x=sqrt(13)}}} or {{{x=-sqrt(13)}}}.