Question 477070
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Let *[tex \Large l] represent the length of the rectangle.  Let *[tex \Large w] represent the width.  We are given that *[tex \Large l\ =\ 3w]


The perimeter of a rectangle is given by *[tex \Large P\ =\ 2l\ +\ 2w]


Substituting:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(w)\ =\ 2(3w)\ +\ 2w]


But since you were given that the perimeter is 144 feet:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2(3w)\ +\ 2w\ =\ 144]


Solve for *[tex \Large w] to get the width.  Calculate *[tex \Large 3w] to get the length.  Calculate *[tex \Large 3w^2] to get the area.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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