<PRE><B>Question 49303</B>
Let one side of a rectangular Stage = A meter

Other side of Rectangula stage = B meter

let us say, A is 2 meter longer than B which means :

A = B + 2 meter

Diagonal D = 10 meters

Apply Pythagoras Theorem : which says : square of A + Square of B = Square of D

in a Rectangle.

Substitute A = B+2 in above equation and rewrite as below:

square of D = square of ( B+2) + square of B

First let us solve : square of ( B + 2)=Sq(B)+Sq(2)+2*B*2=Sq(B)+4+4B

Now : 100 = Sq(B)+4+4B+Sq(B) = 2*Sq(B)+4B+4 let us rewrite as :
100 = 2B^2+4B+4

Now Multiply on eitherside by 2 to give results as below :

200 = 4B^2+8B+8

Now add and subtract 4 on right hand side of the equation to get :

200 = 4B^2 + 8B + 8 + 4 - 4
200 = 4B^2 + 8B + 4 + 4

200 - 4 = 4B^2 + 8B + 4
196 = (2B + 2 )^2

sqrt(196) = 2B + 2
14 = 2B + 2
12 = 2B
B = 6

Therefore answers are : A = B + 2 = 6 + 2 = 8 meter and B= 6 Meter

A = 8 meter / B = 6 meter

How to verify : D^2 = A^2 + B^2
100 = 64 + 36 

Thats all.....
By b.Shridhar

</PRE>