Question 49303
width(leg) = w
length(leg) = w + 2
diagonal length(hypotenuse) = 10
{{{w^2 + (w + 2)^2 = 10^2}}}
{{{w^2 + w^2 + 4w + 4 = 100}}}
{{{2w^2 + 4w - 96 = 0}}}
{{{w^2 + 2w - 48 = 0}}}
{{{(w + 8)(w - 6) = 0}}}
width = 6 because the width can not be negative
length = 6 + 2 = 8