Question 476855
Decide how many solutions this equation has:
x^2 + 3 = 0
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a = 1 ; b = 0 ; c = 3
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discriminant = b^2-4ac = 0^2-4*1*3 = -12
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Since it is negative there are 2 complex-
number solution.
No Real number solutions.
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Cheers,
Stan H.