Question 476817
{{{(64*y^2/(3y^2-12y+12))((3y-6)/8y)}}}


={{{(64y^2/3(y^2-4y+4))(3(y-2)/8y)}}}.....replace {{{-4y}}} with {{{-2y-2y}}}

={{{(64y^2/3(y^2-2y-2y+4))(3(y-2)/8y)}}}


={{{(64y^2/3((y^2-2y)-(2y-4)))(3(y-2)/8y)}}}


={{{(64y^2/3(y(y-2)-2(y-2)))(3(y-2)/8y)}}}


={{{(64y^2/3((y-2)(y-2)))(3(y-2)/8y)}}}....reduce


={{{(cross(64y^2)8y/cross(3)(cross((y-2))(y-2)))(cross(3)cross((y-2))/cross(8y))}}}





={{{8y/(y-2)}}}