Question 476773
{{{6xy=12x}}}

{{{y=12x/6x}}}

{{{y=cross(12)2cross(x)/cross(6)cross(x)}}}

{{{y=2}}}.........a line parallel to {{{x-axis}}}

so, for {{{x=1}}} or any other value of {{{x}}} we have {{{y=2}}}

{{{ graph(500,500, -10, 10, -10, 10,2) }}}

{{{4x+3y=0}}}

{{{3y=0-4x}}}

{{{3y=-4x}}}

{{{y=-(4/3)x}}}

 if {{{x=-3}}} then {{{y=-(4/3)(-3)}}}....->...{{{y=12/3}}}....->...{{{y=4}}}


{{{ graph(500,500, -10, 10, -10, 10, -(4/3)x) }}}