Question 476766


{{{(n^2+2n-24)/( n^2-11n+28)}}}........replace {{{2n}}} with {{{-4n+ 6n}}}, and {{{-11n}}} with {{{-4n-7n}}}


{{{(n^2-4n+ 6n-24)/( n^2-4n-7n+28)}}}.....group


{{{((n^2-4n)+ (6n-24))/( (n^2-4n)-(7n-28))}}}


{{{(n(n-4)+ 6(n-4))/( n(n-4)-7(n-4))}}}


{{{((n+ 6)(n-4))/(( n-7)(n-4))}}}


{{{((n+ 6)cross((n-4)))/(( n-7)cross((n-4)))}}}


{{{(n+ 6)/(n-4)}}}