Question 476674
What is the minimum product of two numbers whose difference is 6? 
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x - y = 6
So x = y+6
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product = xy = (y+6)y = y^2+6y
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You have a quadratic equation:
y^2 + 6y = Product
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The mimimum occurs when y = -b/(2a) = -6/(2*1)= -3
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Solve for "x":
x = y+6
x = -3+6 = 3
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Minimum product = xy = 3*-3 = -9
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Cheers,
Stan H.
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