Question 476548
your equation is:
{{{(7.1*10^(-7))*(8.6*10^(-5))}}}
this is equivalent to:
{{{(7.1)*(8.6)*(10^(-7))*(10^(-5))}}}
since {{{(b^a)*(b*c) = b^(a+c)}}}, this  becomes:
{{{61.06 * 10^((-7)+(-5))}}} which becomes:
{{{61.06 * 10^(-12)}}}
this is equivalent to:
{{{6.106 * 10^(-11)}}} in strict scientific notation where you have 1 digit to the left of the decimal point and the rest of the digits to the right of it.
since {{{6.106 * 10^1}}} is equivalent to 61.06, then your expression became:
{{{6.106 * 10^1 * 10^(-12)}}}
since {{{b^a * b^b = b^(a+b)}}}, this became:
{{{6.106 * 10^(1 + (-12))}}} which equals:
{{{6.106 * 10^(-11)}}}