Question 476570
Let {{{n}}} = one's digit
The number is:
{{{ n + 10*(n + 3) + 100*(n + 3 - 2) }}}
{{{ n + 10n + 30 + 100n + 100 }}}
{{{ 111n + 130 }}}
If the number is odd, n can only be 1,3,5,7 or 9
If {{{ n = 1 }}},
{{{ 111*1 + 130 = 241 }}}
If {{{ n = 3 }}},
{{{ 111*3 + 130 = 463 }}}
If {{{ n = 5 }}},
{{{ 111*5 + 130 = 685 }}}
If {{{ n = 7 }}},
{{{ 111*7 + 130 = 907 }}} (this fails, since the 
10's digit is not {{{ n + 3 }}}
If {{{ n = 9 }}},
{{{ 111*9 + 130 = 1129 }}} (this fails, it's a 4-digit number)