Question 476570
Let {{{x}}} - ones
then {{{(x+3)}}} - tens
{{{(x+3-2)=x+1}}}-hundred digit
{{{system(x<10, x+3<10, x+1<10)}}} => {{{system(x<10, x<7, x<9)}}} =>{{{x<7}}}
The number is odd, so {{{x}}} could be 1 or 3 or 5

if {{{x=1}}} , then {{{x+3=4}}}, {{{x+1=2}}}, the number {{{241}}}
if {{{x=3}}} , then {{{x+3=6}}}, {{{x+1=4}}}, the number {{{463}}}
if {{{x=5}}} , then {{{x+3=8}}}, {{{x+1=6}}}, the number {{{685}}}
Answer: 241, 463, 685