Question 476447
a. the sampling distribution of proportions would be normally distributed, {{{N(p, sqrt((pq)/n))}}}, or N(0.12,0.014).  {{{mu = 0.12}}}, and {{{sigma = 0.014}}}.

b. we want the probability under the standard normal table between 
{{{z = (P - p)/sqrt((pq)/n) = 0.03/0.014 = 2.14}}} and 
{{{z = (P - p)/sqrt((pq)/n) = -0.03/0.014 = -2.14}}}
==> {{{P(-2.14 < z < 2.14) = 0.9838 - 0.0162 = 0.9676}}}

c.  this follows the same procedure as in (b).