Question 476476


{{{x^2+14x=5}}}

{{{x^2+14x-5=0}}}...in order to solve for x, we need to use the quadratic formula


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}...note: {{{a=1}}}, {{{b=14}}} and {{{c=-5}}}


{{{x = (-14 +- sqrt( 14^2-4*1*(-5) ))/(2*1) }}}


{{{x = (-14 +- sqrt( 196+20 ))/2 }}}


{{{x = (-14 +- sqrt( 216))/2 }}}


{{{x = (-14 +- 14.7)/2 }}}


solutions:


{{{x = (-14 + 14.7)/2 }}}

{{{x = (0.7)/2 }}}

{{{x = 0.35 }}}

or

{{{x = (-14 - 14.7)/2 }}}

{{{x = (-28.7)/2 }}}

{{{x = -14.35 }}}


check:

{{{x^2+14x=5}}}...plug in {{{x = 0.35 }}}


{{{(0.35)^2+14(0.35)=5}}}

{{{0.1225+4.9=5}}}

{{{5.0225=5}}}.....round

{{{5=5}}}