Question 476419
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Let the first digit be t
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the 2nd digit...is smaller than its 1st digit by 4.
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Therefore the second digit is t-4.

The number is 10 times the first digit plus the second digit

The number = 10t + t-4 = 11t - 4

Digits' sum = t + t-4 = 2t - 4
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if the number were divided by the digit's sum, the quotient would be 7
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11t - 4
——————— = 7
 2t - 4 

Multiply both sides by (2t - 4)

11t - 4 = 7(2t - 4)

11t - 4 = 14t - 28

    -3t = -24

      t = 8

The second digit is t-4 = 8-4 = 4

So the number is 84.

Edwin</pre>