Question 476386
{{{x2 -2x + 10 = 0}}}
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{a=1}}}, {{{b=-2}}}, {{{c=10}}}
{{{x = (-(-2) +- sqrt((-2)^2-4*1*10 ))/(2*1) }}} 
{{{x = (2 +- sqrt(-36 ))/2 }}} 
{{{x[1] = (2 +6i)/2 }}} or {{{x[2] = (2 -6i)/2 }}}
{{{x[1]=1+3i}}}  or  {{{x[2]=1-3i}}}