<PRE><B>Question 476225</B>
how much water must be added to 260 liters of 75% hydrochloric acid solution to give a mixture with 60% hydrochloric acid?
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let x=liters of water to be added
75%(260)=60%(260+x)
195=156+.6x
.6x=39
x=65 liters
..
ans:
liters of water to be added=65</PRE>