Question 476228
solve this equation: 5/(y-3) - 30/(y^2-9)=1
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5/(y-3)-30/(y^2-9)=1
5/(y-3)-30/(y+3)(y-3)=1
LCD:(y+3)(y-3)
5(y+3)-30=(y+3)(y-3)
5y+15-30=y^2-9
y^2-5y+6=0
(y-2)(y-3)=0
y=2 
or
y=3 (reject, (y-3)≠0