Question 476118
{{{(3x - 15)/(2x + 1)}}} = 0 
multiply both sides by (2x+1)
(2x+1)*{{{(3x - 15)/(2x + 1)}}} = (2x+1)*0 
Cancel the denominator on the left, the right is 0
3x - 15 = 0
Add 15 to both sides
3x = 15
Divide both sides by 3
x = {{{15/3}}}
x = 5
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See if that works in the original equation
{{{(3(5) - 15)/(2(5) + 1)}}} = 0 
{{{(15 - 15)/(10 + 1)}}} = 0 
{{{0/11}}} = 0, (0 divided by any number is 0)