Question 475935
{{{3^(2r)* 3^(r-4)=97}}}
Formula {{{x^n*x^k=x^(n+k)}}}
{{{3^(2r+(r-4))=97}}}
{{{3^(2r+r-4)=97}}}
{{{3^(3r-4)=97}}} take the logarithm of both sides of the equation by the base 3
{{{3r-4=log(3,97)}}}, use scientific calculator for {{{log(3,97)=4.16408}}}
{{{3r-4=4.16408}}} add 4 to the both sides
{{{3r=8.16408}}} divide by 3
{{{r=2.7214}}}