Question 475995
Find the slope of the given line {{{4x+3y=11}}}
{{{3y=-4x+11}}}
{{{y=(-4/3)x+11/3}}}, the slope is {{{m1=(-4/3)}}}
Perpendicular lines are lines whose slopes are negative reciprocals of one another, {{{m1*m2=-1}}}
then the slope of the line that we have to find {{{m2=-1/(m1)}}}
{{{m2=-1/(-4/3)=3/4}}}
The point-slope form of a line uses a point (x1,y1) and a slope (m), to write the equation of a line. This form is given by the equation:
{{{y - y1= m(x - x1)}}}
Point (-8,7) substitue into formula {{{x1=-8}}}, {{{y1=7}}};   {{{m=3/4 }}}
{{{y-7=(3/4)(x-(-8))}}} multiply by 4
{{{4y-28=3x+24}}}
{{{3x-4y=-52}}}