Question 475943
Start with the function of the height of a falling object as a function of time:
{{{h(t) = -(1/2)gt^2+v[0]t+h[0]}}} where: {{{g = 32ft/sec^2}}}(acceleration due to gravity), {{{v[0] = 0}}}( initial velocity), and {{{h[0] = 225}}}(initial height)
When the ball reaches the ground, its height is zero, so set {{{h(t) = 0}}}
{{{0 = -16t^2+225}}} Solve for t.
{{{16t^2 = 225}}}
{{{t^2 = 225/16}}}
{{{t^2 = 14.0625}}}
{{{t = 3.75}}}seconds.