Question 475628
{{{(8bc^3)^(1/3) / (81b^-5c^3)^(3/4)}}} 
:
{{{(8^(1/3)b^(1/3)c^1) / (81^(3/4)b^(-15/4)c^(9/4))}}} = {{{(2b^(1/3)c) / 27b^(-15/4)c^(9/4))}}} = {{{(2b^((1/3)+15/4)) / (27c^((9/4)-(4/4)))}}} = {{{(2b^((4/12)+(45/12))) / (27c^(5/4))}}} = {{{(2b^(49/12)) / (27c^(5/4))}}}
the exponent of b in the numerator is 49/12