Question 475902
Consider college officials in admissions registration, counseling, financial aid campus ministry, food services, and so on. How much money do these people make each year? 
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Suppose you read in your local newspaper that 45 officials in student services earn an average of $50,340 each year.
x-bar = 50,340 
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Assume that the standard deviation is $10,780 for salaries of college officials and student services. 
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Find a 90% confidence interval for the population mean salaries of such personnel. 
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x-bar = 50340
ME = 1.645*10780/[sqrt(45)] = 2643.50
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90%CI: 50340-2643.50 < u < 50340+2643.50
90%CI: 47696.50 < u < 52983.50
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Round your answer to the nearest dollar and don;t forget to use the $ sign. 
2.What is the margin of error for problem 1? Round your answer to the nearest dollar and don;t forget to use the $ sign. 
ME = 1.645*10780/[sqrt(45)] = 2643.50
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Cheers,
Stan H.