Question 49107
Actually, you're wrong!  There are more girls than boys, but it doesn't sound like it, does it?
You can play around with variables, and "let g = # of girls", etc. but that's not the way to do this.  
It says that 1/3 of the girls are 1/5 of the students.  That means that the next 1/3 of the girls is another 1/5 of the students, and the last 1/3 of the girls are yet another 1/5 of the students.  Therefore, if you combine all three 1/3's of the girls, that must be all of the girls.  This also accounts for 1/5 + 1/5 + 1/5 = 3/5 of the students.  So the girls are 3/5 of the students, which means the boys must be the other 2/5 of the students.  So to find a ratio, express it as a fraction of boys on top with fraction of girls on bottom.  This becomes {{{(2/5)/(3/5)}}}.  Now, if you remember how to divide fractions, you flip the bottom fraction over, and then multiply the two together: {{{(2/5) * (5/3)}}}.  Remember, when multiplying fractions, don't actually multiply the numbers out - just cancel the 5 on the top with the 5 on the bottom, and the fraction becomes {{{(2/3)}}}.  Since we put the boys on the top, the answer to your problem is 2 to 3 for boys to girls.  
Look, more girls than boys!!