Question 475656
Find two consecutive odd integers so that the square of the larger exceeds their product by 34.
===========================================
Let n and n+2 be the two consecutive odd integers.
The problem in equation form is:
(n+2)^2 = n(n+2) + 34
square of the larger = their product + 34
Simplify and solve for n:
n^2 + 4n + 4 = n^2 + 2n + 34
2n = 30
n = 15
So the two integers are 15 and 17.