Question 475665
1st,  {{{ p }}} x {{{ p + 7 }}} = {{{ p^2 + 7p }}}
Subtract this from {{{ p^2 + 2p - 28 }}}
I have {{{ -5p - 28 }}} left.
{{{ -5 }}} x {{{ p + 7 }}} = {{{ -5p - 35 }}}
Subtract this from {{{ -5p - 28 }}}
I have {{{ 7 }}} left
The answer is {{{ p - 5 + 7/(p+7) }}}
The {{{ 7/(p+7) }}} is the remainder
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Check answer by multiplying 
{{{ p + 7 }}} x {{{ p - 5 + 7/(p+7) }}}
I get:
{{{ p^2 + 7p - 5p - 35 + 7 }}}
{{{ p^2 + 2p - 28 }}}
OK