Question 474818
D) [3(y + z)]/2


Since w + x = 5(y+z), then 5(w+x) = 25(y+z).

==> 5(w+x+y+z) = 5(w+x) + 5(y+z) = 25(y+z) + 5(y+z) = 30(y+z).

==> {{{(w+x+y+z)/4 = (1/5)*((5(w+x+y+z))/4) =(1/20)*5(w+x+y+z)=(1/20)*30(y+z) = (30/20)(y+z) = (3/2)(y+z) }}}