Question 475625
[8b^(2/3) / 2b^(4/5)]^3/2 
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[4b^[(2/3)-(4/5)]]^(3/2)
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= [4b^[(10-12)/20]]^(3/2)
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= [4b^[-1/10]]^(3/2)
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= [8*b^(-3/20)]
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= [8/b^(3/20)]
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cheers,
Stan H.
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