Question 475597
Area of lot = 32*40 = 1280 sq.m
(40-2x)(32-2x) = area of court

(40-2x)(32-2x)=560

(1280-80x-64x+4x^2)=560

1280+144x+4x^2=560

4x^2+144x+720=0
/4
x^2+36x-180=0

Find the roots of the equation by quadratic formula					
					
a=	1	,b=	36	,c=	-180
					
b^2-4ac=	1296	+	720		
b^2-4ac=	2016				
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}					
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}					
{{{x1=(-12+sqrt(24))/(12)}}}					
x1=(	-36	+	44.9	)/	2
x1=	4.45				
x2=(	-36	-44.9	) /	2	
x2= 	-40.45				
Ignore negative value					
4.45m is the width