Question 475506


{{{y = x + 2}}}..........1...substitute {{{y}}} in 2

{{{x + y = 4}}}..........2

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{{{x + x + 2 = 4}}}........2....solve for {{{x}}}

{{{2x = 4-2}}}

{{{2x =2}}}

{{{x =1}}}

now plug it in {{{y = x + 2}}}..........1

{{{y = 1 + 2}}}

{{{y = 3}}}