Question 15532
total no. of cases= 52c10
if 3ace are selected favorable no. of cases= 4c3*48c7
if 3kings are selected favorable no. of cases= 4c3*48c7
if 3ace and 3kings selected favorable no. of cases= 4c3*4c3*46c4

final result= (4c3*48c7 + 4c3*48c7 + 4c3*4c3*46c4) / 52c10