Question 15704
let 1st digit is less then 2 and remaining more then equal to 2. then we have 2*8*8 favorable no. of cases.
similarly for 2nd and 3rd digit.
so the total no. of favorable cases = 2*8*8 + 8*2*8 + 8*8*2 = 384.
total no. of cases= 10*10*10=1000
ans= 384/1000.