Question 475302
hie there!!

let the width of the rectangle be 'x' meter.
according to the condition provided,
length= 2x-1
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we know that area of a rctangle = (length) x (width)

let us substitute d values of area, length and width
we get,
x(2x-1)=120
thus,
2x^2-x=120
that is
2x^2 -x-120=0
we use the formula 
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
this gives us two solutions,
x=-7.5 or x=8
we know measurement of legth(width is length conventionally)cannot be negative.
therefore, x=8 metre.
and 2x-1= 16-1= 15 metre.
therfore the dimensions of th rectangle are 15 metre and 8 metre