Question 474942
Simply the number of factors of 2010. We can have {a,n} = {1,2010}, {2,1005}, ..., {2010, 1}. 2010 (=2*3*5*67) has 16 factors so there are 16 ordered pairs. However we have to subtract {1,2010} and {2010,1} because n,a > 1, so 14 ordered pairs satisfy the condition.