Question 475270
{{{y + 1 = X^2}}}........1
{{{x^2+ y = 7}}}
{{{x^2= 7-y}}}...........2

therefore y+1=7-y
2y=7-1
2y=6
y=3
plug y in (1)
{{{3+1=x^2}}}
{{{4=x^2}}}
{{{x=+-2}}}