Question 475185


{{{y=-(1/2)x-4}}}.....you have here a linear equation and the graph will be a line..to graph a line you need two points that lie on a line because a line is defined by two points

your equation is also written in {{{slope-intercept}}} form {{{y=mx+-b}}} where {{{m}}} is a {{{slope}}} and {{{b}}} is {{{y-intercept}}}

so, here {{{y=-(1/2)x-4}}} {{{y-intercept}}} is {{{b=-4}}} and that is one point; (0,-4)

now you can find second point: if you take {{{y=0}}} you will find {{{x-intercept}}}

{{{0=-(1/2)x-4}}}

{{{(1/2)x=-4}}}

{{{x=-4/(1/2)}}}

{{{x=-8}}}.....so, the second point is {{{-8,0}}}

now you can plot a line:

{{{ graph( 500, 500, -10, 10, -10, 10,-(1/2)x-4) }}}