Question 475131
solve for x: {{{((9a^2b)^x)(3ab)^4=9^5a^10b^7}}} 
yes, it looks pretty hairy, but let's just plunge into it and see how much we can simplify it
:
We will leave expression with the x exponent alone for while
{{{((9a^2b)^x)(3^4a^4b^4)=9^5a^10b^7}}}
:
{{{((9a^2b)^x)(81a^4b^4)=9^5a^10b^7}}}
;
{{{(9a^2b)^x=(9^5a^10b^7)/(81a^4b^4)}}}
Convert 81 to 9^2
{{{(9a^2b)^x=(9^5a^10b^7)/(9^2a^4b^4)}}}
Using the exponents of like terms we can get rid of the denominator and have 
{{{(9a^2b)^x=(9^3a^6b^3)}}}
We can factor out the exponent on the right to
{{{(9a^2b)^x=(9a^2b)^3}}}
That looks familiar doesn't it, therefore
x = 3