<PRE><B>Question 475131</B>
{{{(9a^2b)^x*(3ab)^4=9^5a^10b^7}}}
= {{{(9a^2b)^x = 9^5a^10b^7/(81a^4b^4)}}}
81 = 9^2
= {{{(9a^2b)^x = 9^3a^10b^7/(a^4b^4)}}}
= {{{(9a^2b)^x = 9^3a^6b^3}}}
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I shoulda spotted that the RHS is the cube of the LHS.
ankor...  did.
I&#39;ll blame it on drugs (headache meds).
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