Question 49156
solve 2x²-3x-2÷10+x-3x²
I can not figure this problem out.. I have tried about 12 times.. this is my last resort.
2x²-3x-2=2X^2-4X+X-2=2X(X-2)+1(X-2)=(X-2)(2X+1)
10+x-3x²=10+6X-5X-3X^2=2(5+3X)-X(5+3X)=(5+3X)(2-X)
HENCE 2x²-3x-2÷10+x-3x²=-(2-X)(2X+1)/(3X+5)(2-X)=-(2X+1)/(3X+5)