Question 475055
  <pre><font face = "Tohoma" size = 4 color = "indigo"><b> 
Hi,
log(base4)(x+2)= 1/3log(base4)64 = log(base4) 64^(1/3) = 1  
{{{root(3,64) = 4}}} and  *[tex \large \ \ \ \ \ \ \ \ \ \ log_4(4) \ = \ 1 \ \ \Rightarrow\ \ 4^1 = 4]
log(base4)(x+2)= 1
 (x+2) = 4^1
 x + 2 = 4
   x = 2