Question 475038
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Hi
Let x,y and z represent the numbers
 x + y + z = 6
 x - y +4z = -8
2x + y + z  = 10

 -x - y - z = -6    |subtracting 1st EQ from 3rd EQ
2x + y + z  = 10
            x = 4

 4 + y + z = 6     |substituting  4 for x
 4 - y +4z = -8
   8 + 5z = -2
        z = -2   and y = 4    (4 + y -2 = 6,  y = 4)
Numbers are: 4 , 4, -2