Question 474798
car leaving wallace x mph
Car leaving Vernonville = x-10 mph


Towards each other so speed = x+x-10==>2x-10

D= 208
t=1h 36 m ===> 8/5 hours
speed = 2x-10

speed = d/t

speed = 208/(8/5)
2x-10 = 208*5/8
2x-10 =26*5
2x-10=180
2x=180+10
2x=190
x=95 speed of one car
other car speed = 85 mph