Question 49110
The sum of the roots of {{{ax^2+bx+c = 0}}}?

Since the the roots are given by:
{{{x = (-b+sqrt(b^2-4ac))/2a}}} and {{{x = (-b-sqrt(b^2-4ac))/2a}}}
Their sum is:
{{{((-b+sqrt(b^2-4ac))/2a) + ((-b-sqrt(b^2-4ac))/2a)}}} = {{{-2b/2a = -b/a}}}